1. Cooling tower cooling water volume
Method one:
Cooling water = 860 × Q (kW) × T / 5000 = 559 m3 / h
T------ coefficient, centrifugal chiller take 1.3, absorption refrigeration unit take 2.5
5000-----The heat taken away per ton of water
Method 2:
Cooling water:
G= 3.6Q/C (tw1-tw2)=559m3/h
Q—Cooling tower cooling heat, kW, about 1.35 times the cooling load of the electric refrigerator, about 2.5 times the absorption type.
C-specific heat of water (4.19kJ/kg.k)
Tw1-tw2—The temperature difference between the inlet and outlet of the cooling tower is generally 5 °C; the compression refrigerator is 4~5°C; the absorption refrigerator is 6~9°C
Cooling tower tonnage = 559 × 1.1 = 614 m3 / h
2. Cooling pump head
Head of cooling water pump
Hp=(hf+hd)+hm+hs+ho
where hf, hd - the total resistance and local resistance of the cooling water pipeline system, mH2O;
hm - condenser resistance, mH2O;
hs - the lifting height of the water in the cooling tower (the height difference from the cooling pool to the nozzle), mH2O; (the open system has, closed system does not have this item)
ho - cooling tower nozzle spray pressure, mH2O, approximately equal to 5 mH2O.
Hp=(hf+hd)+hm+hs+ho=0.02×50+5.8+19.8+5=31.6mH2O
The required lift for the cooling pump = 31.6 × 1.1 = 34.8 mH2O
Cooling water pump flow = 262 × 2 × 1.1 = 576 m3 / h
3. Freezing pump head
Head of chilled water pump
Hp=(hf+hd)+hm+hs+ho
where hf, hd - the total resistance and local resistance of the chilled water pipeline system, mH2O;
hm - evaporator resistance, mH2O;
hs - air conditioner end resistance, mH2O;
ho - two-way control valve resistance, mH2O.
Hp=(hf+hd)+hm+hs+ho=0.02×150+5+2.78+4=14.78mH2O
The required lift for the cooling pump = 14.78 × 1.1 = 16.3 mH2O
Cooling pump flow = 220 × 2 × 1.1 = 484 m3 / h
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